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                                        3. SHPREHJET ME NDRYSHORE (VAZHDIM)61USHTRIMEC Ushtrohuni duke zbatuar1. Thjeshtoni thyesat:a) xyx2 ; b) 2xy8y2 ; c) 10m2n6mn3 ; d) 15x3 y2 z10x2 y3 z.2. Thjeshtoni thyesat:a) 3a – 6b9a ; b) 2x4x + 6y; c) 3(x – 12)12a – ax; d) ab – 6yx(3 – a).3. Thjeshtoni thyesat:a) a2 – aa2 – 1; b) x2 – 4x2 – 4x + 4; c) x2 – y2x2 + xy; d) m3 – 3m2m2 – 9 .1 Thjeshtoni thyesat:a) 3xy4x2 ; b) 6mn9m2 ; c) 12a2b8ab3 ; d) 21a3b2c14a2b3c; e) 15x4y3z512x3y2z4 .2 Në vend të pikave, vendosni shenjat = ose ≠.a) 6x2yz3xy2 .... 2xyb) 15m2x25mx4 .... 3mx c) 2a2bc8ab3c .... 4acb d) 8x2y2z24x2y2z .... 2z.3 Thjeshtoni thyesat:a) 3m – 6n6m ; b) 6x2x + 2y; c) 8(a – 12)12b – ab; d) xy – 3ya(3 – x).4 Thjeshtoni thyesat:a) x2 – xx2 – 1 ; b) x2 – 9x2 – 6x + 9 ; c) x2 – y2x2 – xy; d) a2 – 2a2a2 – 4 .5 Thjeshtoni thyesat:a) p2 – q2p(p – q) ; b) 4a2 – 9b22a2 + 3ab; c) a2 – b2ax – bx; d) c6 – c4c3 + c2 .6 Vërtetoni se vlera e shprehjes ax2 – 2x22ax – 4x nuk varet nga vlera e a (për a ≠ 2).7 Thjeshtoni thyesat:a) x2 + 2xy + y2x2 + xy – ax – ay; a) 8a + 4b2ac + bc – 2ad – bd ; P. [a) x + yx – a;  b) 4c – d]8 Vërtetoni barazimet:a) 12a2b6a3b2 – 8a2 = 6b(3a – 4b) ; b) 2a2b – 2b1 – a4 = – 2ba2 + 1.

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