Page 240 - Demo

234 Përgjigjet12 (–6, –14) dhe 143 , 18 ⎛⎝⎜ ⎞⎠⎟13 a i {x: x d 1} ii x x: 613≥ ⎧⎨⎩⎫⎬⎭ b i 1,26 d x d 12,74 ii x d 0,67 ose x t 3,27 14 a b Vlerësim 11 C, 1  2 2 2 A, 3y  2x 7 3 a i  2m n ii − + 5m n2 1 iii 35m2 b + n2 p q4 a i 4 3 ii 12 5 731− + b 6 25 5 a (x  3)2  4 b 6 x = 7 { y = 11 ose x = 1 { y = 7 xx x x ( 4) 4 2 5 + = + + −⇒ x x + +=1 0 2⇒ D = − ⋅ ⋅ =− < ⇒ 1 4 1 1 3 0 2 . Nuk ka rrënjë reale.8 a i x fi 4 ii 1 5 s s x b 9 x 512 ( ) a b − ≥⇒0 2a ab b − +≥⇒ 2 0 a b ab + ≥ 2⇒ + ≥a b ab213 a (2 1)( 8) u u   b x = −1 or x 314 a x mx x mx + + + − ++ = ( 2) 4 6( 2) 10 0 2 2⇒ + + ++ − − + = x m x mx x mx 4 4 4 6 12 10 0 2 22⇒ + + − += ( 1) 2(2 ) 2 0 m x mx 2 2 b m =− ±2 616 a E gabuar, p.sh. a = 4, b = –5. b E vërtetë: n2 + n { n(n + 1); n ose n + 1 do të jetë çift. c E vërtetë: ( 2) 0 b a − ≥⇒ 2 b ab a − + ≥⇒ 440 2 2b ab a ≥ − 4 4 2 2 d E gabuar, p.sh. n = 4.17 a (0, 9) b (2, 1) c C (3 2, 7 4 2 )   , D (3 2, 7 4 2 )  18 ( 3) 9 ( 2) 4 2 0 x y + −+ − −−= 2 2 ; Qendra C1 (–3, 2); Rrezja r1  15( 1) 1 ( 5) 25 55 0 x y − −+ − − − = 2 2 . Qendra, C2 (1, 5); Rrezja, r2 = 9. Largesa C1C2 = (1−( + − − 3) (5 2) 2 2 [ ] = 5; C1C2 + r1 < r2.Kreu 2Ushtrime 2.1B Arsyetim dhe zgjidhje problemore1 (2a2  2a  5)  (a2  2a  4) a2  1, (a2  1)  (3a  8) a2  3a  9, (a2  2a  4)  (a2  3a  9) a  52 16b2  56ab  49a2 cm23 (6c3 5c2  27c  14) cm34 (a  3)(3a  7) cm25 (2a2x  6ax2  4x3) cm36 a t 5 b 31,25 m7 a t 0, 43, ose 8 sekonda t 0: v 32 m/s, a 56 m/st 43 : v  803 m/s, a 32 m/s2 t 8: v 160 m/s, a 88 m/s2 b x  19 712243 , v  4969 m/s c t 289  4 319 s ose 289  4 319 s a 8 31 m/s2 ose a 8 31 m/s28 a p x2  8x  9, q x2  x  5 b Perimetri = 4(x2  4x  5)c Syprina = x4  8x3  5x2  34x  16